Determine the force of pressure of passengers on the floor of the elevator car

Determine the force of pressure of passengers on the floor of the elevator car, if their mass is 150 kg, and the elevator descends with an acceleration of 0.6 m / s ^ 2.

Initial data: m (mass of passengers in the elevator car) = 150 kg; a (the acceleration with which the lift descends) = 0.6 m / s2.

Reference data: according to the condition g (gravitational acceleration) ≈ 10 m / s2.

The force of pressure of passengers on the floor of the descending elevator car can be determined by the formula: F = P = m * (g – a).

Calculation: F = 150 * (10 – 0.6) = 150 * 9.4 = 1410 N.

Answer: Passengers press on the bottom of the descending elevator car with a force of 1410 N.