Determine the force that acts on a conductor with a long active part of 15 cm

Determine the force that acts on a conductor with a long active part of 15 cm, the current strength in it is 20A, the magnetic induction is 2.4 T.

L = 15 cm = 0.15 m.
I = 20 A.
B = 2.4 T.
F -?
A conductor with a current in a magnetic field is affected by the Ampere force F, which is determined by the formula: F = I * B * L. Where I is the current in the conductor, V is the magnetic induction of the magnetic field, L is the length of the conductor.
F = 20 A * 2.4 T * 0.15 m = 7.2 N.
Answer: the ampere force acts on the conductor with current: F = 7.2 N.