Determine the force with which kerosene acts on a 16cm ^ 2 plug located at a depth of 40cm

We translate all the values ​​from given to the SI system:
S = 16 cm2 = 0.0016 m2
h = 40 cm = 0.4 m
According to Pascal’s law:
The hydrostatic pressure inside the liquid at any depth does not depend on the shape of the vessel in which the liquid is located, and is equal to the product of the density of the liquid, the acceleration of gravity and the depth at which the pressure is determined:
P = ρ * g * h, where ρ is the density of the liquid, g is the free fall acceleration of a body raised above the Earth g = 9.8 m / s2, h is the depth of immersion in the liquid.
The force of water pressure on the plug:
F = P * S, where S is the area of ​​the plug.
Let’s substitute the formula for pressure in the formula for determining the force:
F = P * S = ρ * g * h * S
Determine the density of kerosene according to the reference book:
ρ = 800 kg / m³
Substitute the numerical values ​​and calculate the force:
F = ρ * g * h * S = 800 * 9.8 * 0.4 * 0.0016 = 5 N

Answer: 5 N