Determine the force with which the air presses on the roof of a house 50 m long and 20 m wide at normal atmospheric pressure.

Given:

P = 101325 Pascal – normal atmospheric pressure;

a = 50 meters – the length of the roof of the house;

b = 20 meters – the width of the roof of the house.

It is required to determine F (Newton) – the force with which the air presses on the roof of the house at normal atmospheric pressure.

Assuming that the roof of the house is rectangular, we find the surface area:

s = a * b = 50 * 20 = 1000 square meters.

Then, to determine the force, you must use the following formula:

P = F / s, from here we find:

F = P * s = 101325 * 1000 = 101325000 Newton = 101.3 MN.

Answer: the air pressure force is 101.3 MN.