Determine the formula for a hydrocarbon containing 80% carbon (by mass)

Determine the formula for a hydrocarbon containing 80% carbon (by mass) The relative density of a substance for oxygen is 0.94.

Let’s implement the solution:
1. According to the condition of the problem, write the data:
Given: CxNu – organic matter
W (C) = 80%
D (O2) = 0.94;
M (O2) = 32 g / mol;
Determine: the formula of the hydrocarbon.
2.M (CxHy) = D (O2) * M (O2) = 0.94 * 32 = 30.08 g / mol.
3. Calculations:
Y (C) = m / M = 80/12 = 6.6 mol;
m (C) = Y * M = 6.6 * 12 = 80 g;
m (H) = 100 – 80 = 20 g;
Y (H) = m / M = 20/1 = 20 mol.
4. Consider the ratio:
X: Y = 6.6: 20 = 1: 3;
CH3 is the simplest formula
C2H6 – molecular;
Verification: M (C2H6) = 2 * 12 + 6 = 30 g / mol.
Answer: ethane – C2H6.