Determine the formula for the higher hydroxide of a group IIA element containing 43.24% oxygen by weight.

First, we find the molar mass of the hydroxide

M (hydrox.) = 32 / 0.4324 = 74 g / mol

M (X) = 74g / mol – 34g / yol = 40 g / mol

This is the molar mass of calcium. So the answer is: Ca (OH) 2



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