Determine the formula of a gaseous substance if the mass fraction of carbon is 27.27%

Determine the formula of a gaseous substance if the mass fraction of carbon is 27.27%; oxygen – 72.73%; The molecular weight of this gaseous substance is 44.

Let’s execute the solution:
1. We write down data on the condition of the problem:
Given: M (CxHy) = 44;
W (C) = 27.27%
W (O) = 72.73%
Let’s define the formula of organic matter.
2. Determine the amount of carbon, oxygen:
Y (C) = m / M = 27.27 / 12 = 2.27 mol;
Y (O) = m / M = 72.73 / 16 = 4.54 mol.
3. Ratio:
X: Y = 2.27: 4.54 = 1: 2;
CO2;
Check: M (CO2) = 44 g / mol.
Answer: CO2 is carbon monoxide (2).