Determine the formula of the Intermetallic compound of silver with aluminum if the mass fraction of silver in it is 87%.

Let’s implement the solution:
1. Let’s write down the data on the condition of the problem:
AgxAly – intermetallic compound;
W (Ag) = 87%
M (Ag) = 107.8 g / mol;
M (Al) = 26.9 g / mol;
m (Al) = 100 – 87 = 13 g;
Determine: the formula of the intermetallic compound.
2. Find the amount of silver, aluminum by the formula:
Y (Ag) = m / M = 87 / 107.8 = 0.8 mol;
Y (Al) = m / M = 13 / 26b9 = 0.48 mol.
3. Ratio:
X: Y = 0.8: 0.48 = 1: 2;
4. Formula: Ag2 / Al.
Answer: when alloying the inermetallide, the following was obtained: Ag2 / Al.