Determine the formula of the limiting monohydric alcohol if the mass fraction of carbon in this alcohol is 0.600.

Let’s write down the solution according to the condition of the problem:
1. Given: CnH2n + 1OH – the general formula of alcohols
W (C) = 60% (mass fraction of carbon 0.600);
Determine: molecular formula.
2. Find the amount of carbon:
Y (C) = m / M = 60/12 = 5 mol.
3. Establish the formula:
С5Н11ОН – pentanol.
Answer: amyl alcohol – С5Н11ОН.