Determine the greatest force that a hydraulic press piston with an area of 2700 mm2

Determine the greatest force that a hydraulic press piston with an area of 2700 mm2 can develop if the allowable pressure is 2.3 MPa?

The permissible pressure of the hydraulic press piston can be calculated by the formula:

P = F / S, where P is the permissible pressure of the hydraulic press piston (P = 2.3 MPa = 2.3 * 10 ^ 6 Pa), F is the greatest pressure force, S is the area of the hydraulic press piston (S = 2700 mm2 = 2700 * 10 ^ -6 m2).

Let us express and calculate the greatest pressure force:

F = P * S = 2.3 * 10 ^ 6 * 2700 * 10 ^ -6 = 6210 H = 6.21 kN.

Answer: The greatest pressure force of the hydraulic press piston is 6.21 kN.



One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.