Determine the height of the pendulum ball if it passes the equilibrium position at a speed of 0.05 m (1 m / s)

According to the law of conservation of energy:
mVinitial ^ 2/2 + mghinitial = mVinitial ^ 2/2 + mghinitial
Let’s reduce everything by weight:
V initial ^ 2/2 + gh initial = V final ^ 2/2 + gh final
Now let us take the pendulum in equilibrium position as a reference point. Then h is initial = 0, and at the highest point the speed will be equal to 0, so V is final = 0. Let’s write:
V initial ^ 2/2 = gh final
Let’s express the height:
h final = V final ^ 2 / (2g)
1) h = 0.05 ^ 2 / (2 * 9.8) = 0.0025 / 20 = 0.000125 m = 0.0125 cm = 0.125 mm
2) h = 1 ^ 2 / (2 * 9.8) = 1/20 = 0.05 m = 5 cm