Determine the height of the tower if the body that fell from it was in the fall for 3 s.

V0 = 0 m / s.

g = 10 m / s2.

t = 3 s.

h -?

When falling, only gravity acts on the body, so it moves with the acceleration of gravity g.

The height of the fall of the body with uniformly accelerated motion is determined by the formula: h = V0 * t + g * t ^ 2/2, where V0 is the initial velocity of the body, t is the time of motion of the body, g is the acceleration of gravity.

Since the initial velocity of the body is V0 = 0 m / s, the formula will take the form: h = g * t ^ 2/2.

h = 10 m / s2 * (3 s) ^ 2/2 = 45 m.

Answer: the tower has a height of h = 45 m.