Determine the inductance of the coil, in which the self-induction EMF of 0.5V occurs, if the current decreases

Determine the inductance of the coil, in which the self-induction EMF of 0.5V occurs, if the current decreases by 0.2A in 0.04s.

Initial data: Esi (EMF of self-induction, which arose in the coil) = 0.5 V; Δt (elapsed time) = 0.04 s; ΔI (change in coil current) = 0.2 A.

The inductance of the coil can be determined from the formula for calculating the EMF of self-induction: Esi = -L * ΔI / Δt, whence L = -Esi * Δt / ΔI.

Let’s perform the calculation: L = -0.5 * 0.04 / 0.2 = -0.1 G.

Answer: The inductance of the coil is 0.1 H.