Determine the initial and final speed of the electric train if it covered 160m in 8 seconds with an acceleration of 2 m / s.

Initial data: t (duration of the train movement) = 8 s; S (distance traveled by the train) = 160 m; a (acceleration) = 2 m / s2.

1) Determine the initial speed of the train: S = V0 * t + 0.5 * a * t ^ 2, whence V0 * t = S – 0.5 * a * t ^ 2 and V0 = (S – 0.5 * a * t ^ 2) / t = (160 – 0.5 * 2 * 82) / 8 = 12 m / s.

2) Let’s calculate the final speed of the train: V = V0 + a * t = 12 + 2 * 8 = 28 m / s.

Answer: The initial and final speeds of the electric train are respectively equal to 12 m / s and 28 m / s.