Determine the largest and smallest value of the force acting on a conductor with a current of 0.6m

Determine the largest and smallest value of the force acting on a conductor with a current of 0.6m long at different positions in a uniform magnetic field with an induction of 1.5T and a current of 10A.

L = 0.6 m.

I = 10 A.

B = 1.5 T.

Fаmin -?

Fаmax -?

On a conductor of length L, through which a current with a current strength I flows, in a magnetic field with induction B, the Ampere force Fа acts, the value of which is determined by the formula: Fа = I * B * L * sinα, where ∠α is the angle between the direction of the current in the conductor and vector of magnetic induction B.

With a constant value of the current I, the length of the conductor L and the magnetic induction B, the value of the Ampere force is determined by the angle ∠α.

The maximum value sinα = 1, at ∠α = 90 ° C, the minimum value sinα = 0, at приα = 0 ° C.

Fаmax = 10 A * 1.5 T * 0.6 m * 1 = 9 N.

Fаmin = 10 A * 1.5 T * 0.6 m * 0 = 0 N.

Answer: with the perpendicular arrangement of the conductor with magnetic lines Fаmax = 9 N, with the location of the conductor along the lines of force Fаmin = 0 N.