Determine the length of a nickelin conductor with a cross-sectional area S = 0.60 mm2 connected

Determine the length of a nickelin conductor with a cross-sectional area S = 0.60 mm2 connected to a current source with a voltage of U = 36 V, if the current in the conductor I = 3.0 A. (Nickel resistivity ρ = 0.40 Ohm * mm2 / mm).

Given: S (cross-sectional area of nickeline conductor) = 0.6 mm2; U (voltage at the current source) = 36 V; I (current in the conductor) = 3 A.

Constants: by condition, we take ρ (specific resistance of nickelin) = 0.4 Ohm * mm2 / m.

The length of the nickeline conductor can be determined from the formulas for calculating the resistance: R = U / I = ρ * l / S, whence l = U * S / (I * ρ).

Let’s make a calculation: l = 36 * 0.6 / (3 * 0.4) = 18 m.

Answer: The length of the nickeline conductor is 18 meters.