Determine the length of the mathematical pendulum which in 60 seconds makes 30 oscillations.

Given: T (the duration of the oscillations of the mathematical pendulum) = 60 s; n (the number of oscillations that the pendulum will have time) = 30 oscillations.

Reference values: G (acceleration of free fall) = 9.81 m / s2.

The length of the mathematical pendulum is determined from the formulas for calculating the period of oscillations: T = T / n = 2π * √ (L / G), from where L / G = (T / (n * 2π)) ^ 2 and L = (t / (n * 2π)) ^ 2 * g.

We will calculate: L = (60 / (30 * 2 * 3,14)) ^ 2 * 9.81 = 0.995 m ≈ 1 m.

Answer: The length of the pendulum is 1 meter.



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