Determine the limiting monohydric alcohol if it is known that from 1.15 g

Determine the limiting monohydric alcohol if it is known that from 1.15 g of alcohol under normal conditions sodium displaces 280 ml of hydrogen

2R-OH + 2Na = 2R-ONa + H2

Let’s find the amount of hydrogen substance:

n (H2) = V (H2) / VM = 0.28 / 22.4 = 0.0125 mol;

According to the stoichiometry of the reaction:

n (alcohol) = 2n (H2) = 0.0125 * 2 = 0.025 mol;

Let’s find the molar mass of alcohol:

M (alcohol) = m (alcohol) / n (alcohol) = 1.15 / 0.025 = 46 g / mol;

The molar mass found corresponds to ethanol C2H5OH.

Answer: C2H5OH.