# Determine the magnitude of the force under which a body weighing 120 kg in 5 seconds.

September 12, 2021 | education

| **Determine the magnitude of the force under which a body weighing 120 kg in 5 seconds. acquires a speed of 500 m / s. Neglect friction.**

Given:

m = 120 kilograms – the mass of the body that moves under the influence of the force F;

t = 5 seconds – time interval;

dV = 500 meters per second – the speed that the body acquires over a period of time t.

It is required to determine F (Newton) – the value of the force.

Let’s find the acceleration with which the body moves:

a = dV / t = 500/5 = 100 m / s ^ 2.

Then the force will be equal to:

F = m * a = 120 * 100 = 12000 Newton = 12 kN.

Answer: The magnitude of the force will be 12 kN.

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