Determine the magnitude of the force under which a body weighing 120 kg in 5 seconds. acquires a speed of 500 m / s. Neglect friction.
m = 120 kilograms – the mass of the body that moves under the influence of the force F;
t = 5 seconds – time interval;
dV = 500 meters per second – the speed that the body acquires over a period of time t.
It is required to determine F (Newton) – the value of the force.
Let’s find the acceleration with which the body moves:
a = dV / t = 500/5 = 100 m / s ^ 2.
Then the force will be equal to:
F = m * a = 120 * 100 = 12000 Newton = 12 kN.
Answer: The magnitude of the force will be 12 kN.
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