Determine the mass and chemical amount of aluminum hydroxide and sulfuric acid.

Determine the mass and chemical amount of aluminum hydroxide and sulfuric acid. Necessary to obtain a salt of aluminum sulfate weighing 68.4 g.

2Al (OH) 3 + 3H2SO4 = Al2 (SO4) 3 + 6H2O
2 * 78 3 * 98 342
156 g – 342 g
x g – 68.4 g
x = 68.4 * 156/342 = 31.2 g
294 g – 342 g
y gr – 68.4 gr
y = 294 * 68.4 / 342 = 58.8 g
Answer: 31.2 g Al (OH) 3
58.8 g H2SO4



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