Determine the mass and volume of chlorine that will be required to form 73 g of hydrogen chloride.

univerkov | August 16, 2021 | education

Сl2 + H2 → 2HCl.

Formulas required to solve: n = m / M; n = V / Vm.

M (HCl) = 1 + 35.5 = 36.5 g / mol.
n (HCl) = m / M = 73g / (36.5 g / mol) = 2 mol.
n (HCl) is 2 times more than n (Cl2), therefore,
n (Cl2) = 2 mol / 2 = 1 mol.
M (Cl2) = 35.5 * 2 = 71 g / mol.
m (Cl2) = n * M = 1 mol * 71 g / mol = 71 g.
V (Cl2) = n * Vm = 1 mol * (22.4 L / mol) = 22.4 L.

Answer: m (Cl2) = 71g. V (Cl2) = 22.4 liters.

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