Determine the mass and volume of hydrogen during the decomposition of methane with a volume of 300 liters. CH4 = C + 2H2

Solution:

1. Let us write the reaction equation for the decomposition of methane:

CH4 = C + 2H2;

2. Let’s find the amount of substance in methane:

300 / 22.4 = 13.393 mol;

3. The amount of substance in hydrogen is equal to 26.786 mol, since there is a factor in front of hydrogen that is 2 times greater than in front of methane. Let’s find the volume of hydrogen:

26.786 * 22.4 = 600 liters;

4. Find the mass of hydrogen:

26.786 * 2 = 53.572 grams;

Answer: the volume of hydrogen is 600 liters, the mass of hydrogen is 53.572 grams.