Determine the mass and volume of hydrogen that will be released during the interaction of 130

Determine the mass and volume of hydrogen that will be released during the interaction of 130 grams of zinc with hydrochloric acid.

Zinc is readily soluble in hydrochloric acid:

Zn + 2HCl → ZnCl2 + H2;

The amounts of dissolved zinc and synthesized hydrogen are equivalent.

Let’s determine the chemical amount of zinc.

M Zn = 65 grams / mol;

N Zn = 130/65 = 2 mol;

The same molar amount of hydrogen will be synthesized.

Find the volume of 2 mol of hydrogen. Let’s multiply the amount of gas by the volume of 1 mole of gas.

V H2 = 22.4 x 2 = 44.8 liters;

The mass of hydrogen will be:

M H2 = 2 grams / mol;

m H2 = 2 x 2 = 4 grams;