Determine the mass and volume of hydrogen that will be released during the interaction of 130 grams of zinc with hydrochloric acid.
Zinc is readily soluble in hydrochloric acid:
Zn + 2HCl → ZnCl2 + H2;
The amounts of dissolved zinc and synthesized hydrogen are equivalent.
Let’s determine the chemical amount of zinc.
M Zn = 65 grams / mol;
N Zn = 130/65 = 2 mol;
The same molar amount of hydrogen will be synthesized.
Find the volume of 2 mol of hydrogen. Let’s multiply the amount of gas by the volume of 1 mole of gas.
V H2 = 22.4 x 2 = 44.8 liters;
The mass of hydrogen will be:
M H2 = 2 grams / mol;
m H2 = 2 x 2 = 4 grams;
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