# Determine the mass and volume of hydrogen that will be released during the interaction of 130

September 15, 2021 | education

| **Determine the mass and volume of hydrogen that will be released during the interaction of 130 grams of zinc with hydrochloric acid.**

Zinc is readily soluble in hydrochloric acid:

Zn + 2HCl → ZnCl2 + H2;

The amounts of dissolved zinc and synthesized hydrogen are equivalent.

Let’s determine the chemical amount of zinc.

M Zn = 65 grams / mol;

N Zn = 130/65 = 2 mol;

The same molar amount of hydrogen will be synthesized.

Find the volume of 2 mol of hydrogen. Let’s multiply the amount of gas by the volume of 1 mole of gas.

V H2 = 22.4 x 2 = 44.8 liters;

The mass of hydrogen will be:

M H2 = 2 grams / mol;

m H2 = 2 x 2 = 4 grams;

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