Determine the mass fraction of elements in Fe2O3. Express the found mass fractions as a percentage.

1.M (Fe₂O₃) = 2Ar (Fe) + 3Ar (O) = 2 × 56 + 3 × 16 = 112 + 48 = 160 g / mol
2.ω (Fe) = 112/160 × 100% = 70%
3.ω (O) = 48/160 × 100% = 30%
Answer: 30% and 70%



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