Determine the mass fraction of hydrogen in a mixture of nitrogen, hydrogen and carbon dioxide, the volume

Determine the mass fraction of hydrogen in a mixture of nitrogen, hydrogen and carbon dioxide, the volume fractions of which correspond to 35%, 60% and 5%

1. Let the chemical amount of a gas mixture be 1 mol:

n (mixture) = 1 mol;

2. find the amount of all gases in the mixture:

n (gas) = ϕ (gas) * n (mixture);

n (N2) = 0.35 * 1 = 0.35 mol;

n (H2) = 0.6 * 1 = 0.6 mol;

n (CO2) = 0.05 * 1 = 0.05 mol;

3.Calculate the masses of gases in the mixture:

m (gas) = n (gas) * M (gas);

m (N2) = 28 * 0.35 = 9.8 g;

m (H2) = 2 * 0.6 = 1.2 g;

m (CO2) = 44 * 0.05 = 2.2 g;

4. find the mass of the gas mixture:

m (mixture) = m (N2) + m (H2) + m (CO2) = 9.8 + 1.2 + 2.2 = 13.2 g;

5.determine the mass fraction of hydrogen:

w (H2) = m (H2): m (mixtures) = 1.2: 13.2 = 0.091 or 9.1%.

Answer: 9.1%.