Determine the mass fraction of iron in iron sulfate (2) FeSO4.

Let’s calculate the molar mass of iron sulfate (2):
M (FeSO4) = 56 + 32 + 16 * 4 = 152 g / mol
Now, let’s find the mass fraction of iron:
w (Fe) = 56/152 * 100% = 36.84%



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