Determine the mass fraction of salt in the solution obtained by draining 150 g of 10% and 450 g of 60% solutions.

1. Let’s calculate the mass of salt in the first solution:

m1 (salt) = w1 (salt) * m1 (solution) = 0.1 * 150 = 15 g;

2. find the mass of salt from the second solution:

m2 (salt) = w2 (salt) * m2 (solution) = 0.6 * 450 = 270 g;

3.Calculate the total mass of salt:

mtotal (salts) = m1 (salts) + m2 (salts) = 15 + 270 = 285 g;

4.determine the mass of the resulting solution:

mpol (solution) = m1 (solution) + m2 (solution) = 150 + 450 = 600 g;

5.Set the mass fraction of salt in the resulting solution:

wp (salt) = mtot (salt): mp (solution) = 285: 600 = 0.475 or 47.5%.

Answer: 47.5%.