Determine the mass fraction of salt in the solution obtained by mixing 150 g 10% and 450 g 80% solutions of this salt.

Given:
m1 solution (salt) = 150 g
ω1 (salt) = 10%
m2 solution (salt) = 450 g
ω2 (salt) = 80%

To find:
ω3 (salt) -?

Decision:
1) m1 (salts) = ω1 (salts) * m1 solution (salts) / 100% = 10% * 150/100% = 15 g;
2) m2 (salt) = ω2 (salt) * m2 solution (salt) / 100% = 80% * 450/100% = 360 g;
3) m3 (salt) = m1 (salt) + m2 (salt) = 15 + 360 = 375 g;
4) m3 solution (salt) = m1 solution (salt) + m2 solution (salt) = 150 + 450 = 600 g;
5) ω3 (salt) = m3 (salt) * 100% / m3 solution (salt) = 375 * 100% / 600 = 62.5%.

Answer: The mass fraction of salt in the resulting solution is 62.5%.



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