Determine the mass fraction of sulfur in technical sulfur, if, when burning 18 g of technical

Determine the mass fraction of sulfur in technical sulfur, if, when burning 18 g of technical sulfur, 10 liters were formed. sulfur oxide?

The sulfur oxidation reaction is described by the following chemical equation:

S + O2 = SO2;

To obtain 1 mole of sulfur oxide, 1 mole of sulfur is required.

Let’s calculate the amount of substance in 10 liters of sulfur oxide.

1 mole of ideal gas normally takes on a volume of 22.40 liters.

N SO2 = 10 / 22.40 = 0.446 mol;

Let’s calculate the weight of the same amount of pure sulfur.

M S = 32 grams / mol;

0.446 x 32 = 14.272 grams;

The sulfur content is equal to:

K S = 14.272 / 18 = 0.7929 = 79.29%;