Determine the mass fraction (%) of water in copper sulfate?

First, let’s calculate the molar mass of copper sulfate CuSO4:

M (CuSO4 × 5H2O) = M (CuSO4) + 5 M (H2O) = 160+ 5 × 18 = 160 + 90 = 250 g / mol.

Let’s make the proportion and find the mass fraction of water in the crystalline hydrate:

250 g (mass 1 mol CuSO4 × 5 H2O) – 1 or 100%

90 g (mass 5 mol of water) – x

90 × 1 ÷ 250 = 36%

Therefore, the mass fraction of water in copper sulfate is 36%



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