Determine the mass fractions of elements calcium, carbon, oxygen in CaCO3.

univerkov | November 26, 2020 | education

First, we consider the molar mass of a substance: 1) 40 + 12 + 16 * 3 = 40 + 12 + 48 = 100g / mol
Now we count the percentage
2) W (Ca) = m (Ca) / m (CaCO3) * 100% = 40/100 * 100% = 0.4 = 40%
3) W (C) = m (C) / m (CaCO3) * 100% = 12/100 * 100% = 0.12 = 12%
4) W (O) = m (O) / m (CaCO3) * 100% = 48/100 * 100% = 0.48 = 48%
Answer: W (Ca) = 40%; W (C) = 12%; W (O) = 48%

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