Determine the mass fractions of elements in magnesium nitrate Mg (NO3) 2.

univerkov | August 11, 2021 | education

The relative molecular weight of magnesium nitrate
Mr (Mg (NO3) 2) = Ar (Mg) + 2 Ar (N) + 6 Ar (O) = 24 + 2 × 14 + 6 × 16 = 148.
Mass fraction of magnesium
w (Mg) = Ar (Mg) / Mr (Mg (NO3) 2) × 100% = 24/148 × 100% = 16.2%.
Mass fraction of nitrogen
w (N) = 2 Ar (N) / Mr (Mg (NO3) 2) × 100% = 28/148 × 100% = 18.9%.
Mass fraction of oxygen
w (O) = 6 Ar (O) / Mr (Mg (NO3) 2) × 100% = 96/148 × 100% = 64.9%.

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