Determine the mass of 3 * 10 ^ 23 molecules of hydrogen bromide.
| March 16, 2021 | education
1. Find the chemical amount of hydrogen bromide:
n (HBr) = N (HBr molecules): Na;
n (HBr) = 3 * 1023: 6.02 * 1023 = 0.4983 mol;
2.Calculate the mass of a portion of HBr:
m (HBr) = n (HBr) * M (HBr);
M (HBr) = 1 + 80 = 81 g / mol;
m (HBr) = 0.4983 * 81 = 40.3623 g.
Answer: 40.3623 g.
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