Determine the mass of 7.84 L of NH3.

Given: V (NH3) = 7.84 L, n – moles, Vm = 22.4;
Find: m (NH3);
1) n = V / Vm = 7.84 / 22.4 = 0.35 mol;
2) m = M × n = 0.35 × (14 + 3) = 5.95g.
Answer: 5.95g



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