Determine the mass of a 19.6% sulfuric acid solution that will be required to obtain 11.65 barium sulfate.
September 7, 2021 | education
| n (H2SO4) = n (BaSO4) = m (BaSO4) / M (BaSO4) = 11.65 / 233 = 0.05 mol;
m (H2SO4) = n (H2SO4) * M (H2SO4) = 0.05 * 98 = 4.9 g;
m (H2SO4 solution) = m (H2SO4) / w (H2SO4) = 4.9 / 0.196 = 25 g.
w is the mass fraction of the solute.
Answer: m (H2SO4 solution) = 25 g.
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