Determine the mass of a cast iron piece with a volume of 50 cm³.

Given: V (volume of cast iron part taken) = 50 cm3 (in SI system V = 50 * 10 ^ -6 m3).

Constants: ρh (density of cast iron) = 7 * 10 ^ 3 kg / m3.

To calculate the mass of the cast iron part taken, we apply the formula: m = ρh * V.

Calculation: m = 7 * 10 ^ 3 * 50 * 10 ^ -6 = 0.35 kg or 350 g.

Answer: The mass of the cast iron part taken is 350 g.



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