Determine the mass of a gold bar containing the same number of atoms as a 0.5 kg

Determine the mass of a gold bar containing the same number of atoms as a 0.5 kg iron bar. The molar mass of gold is 197 * 10 ^ -3, and iron is 57 * 10 ^ -3

Initial data: m1 (mass of an iron bar) = 0.5 kg.

Constants: according to the condition M1 (molar mass of iron) = 57 * 10-3 kg / mol; M2 (molar mass of gold) = 197 * 10-3 kg / mol.

The mass of a gold bar can be determined from the equality: m1 / M1 = N (number of atoms) / Na (Avogadro’s number) = m2 / M2, whence m2 = m1 * M2 / M1.

Let’s calculate: m2 = 0.5 * 197 * 10-3 / (57 * 10-3) = 1.728 kg.

Answer: The weight of the gold bar will be 1.728 kg.