Determine the mass of a load that can be lifted with a steel wire with an acceleration

Determine the mass of a load that can be lifted with a steel wire with an acceleration of 2m / s ^ 2 if the wire can withstand a maximum load of 6kN.

Initial data: a (acceleration of the load, which is lifted on the wire) = 2 m / s ^ 2; F (maximum load (pulling force) that the steel wire can withstand) = 6 kN = 6 * 10 ^ 3 N.

Reference values: g (acceleration due to gravity) = 10 m / s ^ 2.

The equation that will turn out when the forces are projected onto one axis: m * a = F – m * g.

F = m * a + m * g; F = m * (a + g); m = F / (a + g).

Let’s perform the calculation:

m = 6 * 10 ^ 3 / (2 + 10) = 500 kg.

Answer: The maximum weight of the cargo is 500 kg.