Determine the mass of a load vibrating on a spring with a stiffness of 36 N / m, if it makes 10 vibrations in 10 seconds.

These tasks: k (stiffness of the spring to which the load was suspended) = 36 N / m; t (duration of oscillations) = 10 s; n (the number of vibrations of the weight on the spring) = 10 vibrations.

1) Calculate the oscillation period: T = t / n = 10/10 = 1 s.

2) Calculate the spring stiffness of the obtained mathematical pendulum: T = 2Π * √ (m / k), whence m / k = T ^ 2 / 4Π ^ 2 and m = T ^ 2 * k / 4Π ^ 2 = 12 * 36 / ( 4 * 3.14 ^ 2) = 0.913 kg (913 g).

Answer: A weight of 913 grams was suspended from the spring.