Determine the mass of a solution of sulfuric acid with a mass fraction of 10% necessary for the complete

Determine the mass of a solution of sulfuric acid with a mass fraction of 10% necessary for the complete displacement of silicic acid from 244 g of a solution of sodium silicate with a mass fraction of 20%

When sodium silicate and sulfuric acid interact, the following chemical reaction occurs:

Na2SiO3 + H2SO4 = Na2SO4 + H2SiO3;

Let’s find the chemical amount of sodium silicate:

For this purpose, we divide its weight by the mass of 1 mole of the substance.

M Na2SiO3 = 23 x 2 + 28 + 16 x 3 = 122 grams / mol;

n Na2SiO3 = 244 x 0.2 / 122 = 0.4 mol;

The same amount of silicic acid can be obtained. This will require an equivalent amount of sulfuric acid.

Let’s calculate its weight.

For this purpose, we multiply the amount of the substance by its molar weight.

M H2SO4 = 2 + 32 + 16 x 4 = 98 grams / mol;

m H2SO4 = 0.4 x 98 = 39.2 grams;

The mass of a 10% solution will be 39.2 / 0.1 = 392 grams;