Determine the mass of a solution with a mass fraction of sulfuric acid of 5%, which will be required

Determine the mass of a solution with a mass fraction of sulfuric acid of 5%, which will be required for the reaction with 4 g of copper (II) oxide.

Given:
W (H2SO4) = 5%
m (CuO) = 4 g
To find:
m (solution) =?
Decision:
1) Find the mass of the substance.
n = m / M
M (CuO) = 64 + 16 = 80 g / mol
n (CuO) = 4g: 80g / mol = 0.05 mol (since 1: 1, then the amount of H2SO4 mol = 0.05)
n (H2SO4) = 0.05 mol x 98 g / mol = 4.9 g
2) Find the mass of the solution
W = (m substance: m solution) x 100%
m solution = m substance: W
m solution = 4.9 g: 0.05 = 98 g
Answer: m (solution) = 98 g.