Determine the mass of acetic acid obtained from alcohol as a result of fermentation of 200 kg

Determine the mass of acetic acid obtained from alcohol as a result of fermentation of 200 kg of glucose with a mass fraction of impurities of 10%.

In order to determine the mass of acetic acid, we first compose the reaction equations and then compose and solve the proportion.

Let’s calculate the mass:

m (C6H12O6) = 200 * 0.9 = 180 kg.

We draw up the reaction equation and make up the proportion:

180 kg x kg
C6H12O6 = 2C2H5OH + 2CO2
180 grams 92 grams

We are looking for an unknown extreme term of the proportion:

x = (180 * 92) / 180 = 92 kg.

Let’s compose the following reaction equation and solve the proportion:

92 kg x2 kg
C2H5OH + [O] = CH3COOH
46 grams 60 grams.

x2 = (92 * 60) / 46 = 120 kg.