Determine the mass of acetic acid required to obtain methyl acetate weighing 518 grams.

Let’s write down the equation of the process:

CH3COOH + CH3OH = CH3COO – CH3 + H2O – esterification, methyl acetate was formed;
Let’s make the calculations:
M (CH3COOH) = 60 g / mol;

M (methyl acetate) = 74 g / mol.

Let’s determine the amount of ether:
Y (ether) = m / M = 518/74 = 7 mol;

Y (CH3COOH) = 7 mol since the amount of substances is 1 mol.

4. Find the mass of acid:

m (CH3COOH) = Y * M = 7 * 60 = 420 g

Answer: you need acetic acid weighing 420 g