Determine the mass of acetic acid that can be obtained by oxidation of a 130 g ethanol

Determine the mass of acetic acid that can be obtained by oxidation of a 130 g ethanol solution with a mass fraction of 40% alcohol

1) Let’s write down the oxidation of alcohol in general form (since the oxidation method is not specified in the task; in any case, the amount of acid will be equal to the amount of alcohol):

C2H5OH + 3 [O] → CH3COOH + H2O

2) Find the amount of alcohol substance:

m (C2H5OH) = m (p-pa) * ω (C2H5OH) = 130 * 0.4 = 52 g;

n (C2H5OH) = m (C2H5OH) / Mr (C2H5OH 0 = 52/46 = 1.13 mol;

3) Find the mass of acetic acid:

n (CH3COOH) = n (C2H5OH) = 1.13 mol;

m (CH3COOH) = n (CH3COOH) * Mr (CH3COOH) = 1.13 * 60 = 67.8 g.

Answer: 67.8 g.