Determine the mass of acetylene formed from methane with a volume of 6.72 liters. Assume the product yield to be 100%.

2CH4 = C2H2 + 3H2
n (CH4) = V \ Vm = 6.72 \ 22.4 = 0.3 mol
for ur-th p-and n (C2H2) = 0.3: 2 = 0.15 mol
m (C2H2) = nM = 0.15 * 26 = 3.9 g
Answer: m (C2H2) = 3.9 g



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