Determine the mass of air m located in a room with dimensions of 6 * 4 * 3m at a temperature of t = 20
Determine the mass of air m located in a room with dimensions of 6 * 4 * 3m at a temperature of t = 20 degrees C and under a pressure of p = 100kPa. The molar mass of air is M = 0.029 kg / mol.
a = 6 m.
b = 4 m.
h = 3 m.
t = 20 ° C.
P = 100 kPa = 100,000 Pa.
M = 0.029 kg / mol.
R = 8.31 m ^ 2 * kg / s ^ 2 * K * mol.
m -?
Let us write the Mendeleev-Cliperon equation: P * V = m * R * T / M, where P is the gas pressure, V is the gas volume, m is the gas mass, R is the universal gas constant, T is the absolute temperature, M is the molar mass of air …
m = P * V * M / R * T.
The room has the shape of a rectangular parallelepiped, so V = a * b * h.
We find the absolute temperature by the formula: T = 273 + t.
m = P * a * b * h * M / R * (273 + t).
m = 100000 Pa * 6 m * 4 m * 3 m * 0.029 kg / mol / 8.31 m ^ 2 * kg / s ^ 2 * K * mol * (273 + 20 ° C) = 85.75 kg.
Answer: in the room m = 85.75 kg of air.