Determine the mass of air m located in a room with dimensions of 6 * 4 * 3m at a temperature of t = 20

Determine the mass of air m located in a room with dimensions of 6 * 4 * 3m at a temperature of t = 20 degrees C and under a pressure of p = 100kPa. The molar mass of air is M = 0.029 kg / mol.

a = 6 m.

b = 4 m.

h = 3 m.

t = 20 ° C.

P = 100 kPa = 100,000 Pa.

M = 0.029 kg / mol.

R = 8.31 m ^ 2 * kg / s ^ 2 * K * mol.

m -?

Let us write the Mendeleev-Cliperon equation: P * V = m * R * T / M, where P is the gas pressure, V is the gas volume, m is the gas mass, R is the universal gas constant, T is the absolute temperature, M is the molar mass of air …

m = P * V * M / R * T.

The room has the shape of a rectangular parallelepiped, so V = a * b * h.

We find the absolute temperature by the formula: T = 273 + t.

m = P * a * b * h * M / R * (273 + t).

m = 100000 Pa * 6 m * 4 m * 3 m * 0.029 kg / mol / 8.31 m ^ 2 * kg / s ^ 2 * K * mol * (273 + 20 ° C) = 85.75 kg.

Answer: in the room m = 85.75 kg of air.



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