Determine the mass of aluminum displaced from the sulfuric acid solution by hydrogen with a volume of 6.72 liters.

The reaction of interaction of aluminum with sulfuric acid is described by the following chemical equation:

2Al + 3H2SO4 (diluted) = Al2 (SO4) 3 + 3H2;

When 2 metal molecules dissolve, 3 hydrogen molecules are released.

Let’s calculate the chemical amount of a substance in 6.72 liters of hydrogen.

1 mole of ideal gas normally takes on a volume of 22.40 liters.

N H2 = 6.72 / 22.40 = 0.3 mol;

This amount of hydrogen will be released upon dissolution of 0.3 / 3 x 2 = 0.2 mol of metallic aluminum.

M Al = 27 grams / mol;

m Al = 0.2 x 27 = 5.4 grams;