Determine the mass of aluminum ions contained in 68.4 g of aluminum sulfate solution

Determine the mass of aluminum ions contained in 68.4 g of aluminum sulfate solution with a mass fraction of aluminum sulfate in the solution of 0.05.

Let’s calculate the weight of aluminum sulfate in solution.

m Al2 (SO4) 3 = 68.4 x 0.05 = 3.42 grams;

Let’s calculate the chemical amount of the substance of this salt.

M Al2 (SO4) 3 = 27 x 2 + (32 + 16 x 4) x 3 = 342 grams / mol;

N Al2 (SO4) 3 = 3.42 / 342 = 0.01 mol;

This amount of salt contains 0.01 x 2 = 0.02 mol of metallic aluminum.

Let’s calculate its weight.

M Al = 27 grams / mol;

m Al = 0.02 x 27 = 0.54 mol;