Determine the mass of aluminum oxide obtained by the interaction of 13.5 grams of aluminum with oxygen.

The combustion reaction of aluminum is described by the following chemical reaction equation:

4Al + 3O2 = 2Al2O3;

From two moles of aluminum, one mole of its oxide is formed.

Determine the amount of substance contained in 13.5 grams of aluminum:

N Al = 13.5 / 27 = 0.5 mol;

During oxidation, 0.5 / 2 = 0.25 mol of aluminum oxide is formed;

Let’s determine the mass of this oxide.

M Al2O3 = 27 x 2 + 16 x 3 = 102 grams / mol;

m Al2O3 = 0.25 x 102 = 25.5 grams;