Determine the mass of aluminum oxide that can be obtained from 23.4 g of aluminum hydroxide.

univerkov | January 17, 2021 | education

Given:
m (Al (OH) 3) = 23.4 g
To find:
m (Al2O3)
Decision:
2Al (OH) 3 = Al2O3 + 3H2O
n (Al (OH) 3) = m / M = 23.4 g / 78 g / mol = 0.3 mol
n (Al (OH) 3): n (Al2O3) = 2: 1
n (Al2O3) = 0.3 mol / 2 = 0.15 mol
m (Al2O3) = n * M = 0.15 mol * 102 g / mol = 15.3 g
Answer: 15.3 g

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